3:25 p.m.
On 04/05/16 14:07, Cole Robinson wrote:
On 05/04/2016 06:54 AM, Paul Carlton wrote:
> Hi
>
> I'm trying to create a volume in an existing storage pool using python by
> calling createXML() on the pool object.
> If the file that is the subject of the new volume exists you get and error,
> also if it doesn't exist
>
> I worked out that specifying
>
> <source>
> <path>path to copy of file</path>
> </source>
>
> works, seemingly by copying the 'source' file to the intended location of
the
> volume file
>
> However I am concerned about the overhead of copying the file, is there a way
> to tell it to move the file (i.e. rename)
Unfortunately there isn't any simple API to 'rename' a storage volume
- Cole
Actually I don't want to rename a storage pool, in my inept attempt a
brevity I failed to explain myself clearly.
I want to create a raw format file in a directory that is referenced by
directory storage pool and register it as a storage volume
If I place the file in the directory then try to create a storage volume
to reference it the operation fails due to the file already existing.
however if I try to create the storage pool then copy the file to the
directory it fails to create the storage pool because the file does not
exist.
I figured out that if I create the file in another directory then create
the storage volume as follows...
def create_volume(self, vol_name, src_path):
def create_vol_xml(name, src):
xml = """<volume type='file'>
<name>{name}</name>
<allocation
unit='bytes'>{allocation}</allocation>
<capacity unit='bytes'>{capacity}</capacity>
<source>
<path>{src_path}</path>
</source>
<target>
<permissions>
<mode>{mode}</mode>
<owner>{uid}</owner>
<group>{gid}</group>
</permissions>
</target>
</volume>"""
stat = os.stat(src)
qmeu_info = images.qemu_img_info(src)
return xml.format(**{'name': name,
'capacity': qmeu_info.virtual_size,
'allocation': qmeu_info.disk_size,
'src_path': src,
'format': qmeu_info.file_format,
'mode': oct(stat.st_mode)[-3:],
'uid': stat.st_uid,
'gid': stat.st_gid})
vol_xml = create_vol_xml(vol_name, src_path)
self._vols[vol_name] = self._pool.createXML(vol_xml, 0)
Where 'src_path' is the path to a file in another directory it seems to
copy src_path to my storage pool directory as 'vol_name' and
creates a storage volume that references it.
This is fine except, my concern is what if the file is very large the
copy operation could take a long time and we'd use twice the
disk space we should do.
Since I could not find any documentation on the <source> elements for a
directory pool's volume xml I was wondering if there
was a setting that would make it move/rename src_file to the vol_name
file in my pool directory rather than copy it?
--
Paul Carlton
Software Engineer
Cloud Services
Hewlett Packard
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