On Wed, Jul 18, 2012 at 11:22:00AM +0100, Morgan Cox wrote:
Hi
I was under the impression that virt-clone would create new UUId,s etc
where as virt-resize doesn't ?
In my previous message I said:
"[...] plus it [virt-clone] makes a handful of changes to the
libvirt config. You can do most of this by alternate means."
All I am trying to do is use a VM (in LVM) as a template to use to
clone .
The templates are only about 3GB - so to deploy the template I need to
resize them.
This is why i did this
TEMPLATE -> [virt-clone] -> new_vm.tmp (to create new UUIDs , etc)
If virt-clone doesn't work then you should just copy and resize the
disk image using one step of virt-resize, create a new libvirt XML
configuration, and finally 'virsh define' the new guest. This would
involve just a single copy and is about the most efficient way of
doing it (even using qcow2 or LUN clones / FlexClone is unlikely to be
better).
If there is a more sensible way of doing this I would like to know !
See above.
Anyway is there a way of forcing being able to copy to an existing
LVM
partition ?? As mentioned I could do it fine in Ubuntu 10.04 not
12.04 - i.e do I need to recompile libvirt, etc ?
$ virt-resize /dev/vg/lv_template /dev/vg/lv_new
Rich.
--
Richard Jones, Virtualization Group, Red Hat
http://people.redhat.com/~rjones
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