On 8/20/20 10:35 AM, Peter Krempa wrote:
> On Tue, Jul 07, 2020 at 21:46:25 +0200, Michal Privoznik wrote:
> > For libvirt, the volume is just a binary blob and it doesn't
> > interpret data on volume upload/download. But as it turns out,
> > this unspoken assumption is not clear to our users. Document it
> > explicitly.
> >
> > Suggested in:
https://bugzilla.redhat.com/show_bug.cgi?id=1851023#c17
> >
> > Signed-off-by: Michal Privoznik <mprivozn(a)redhat.com>
> > ---
> > src/libvirt-storage.c | 8 ++++++--
> > 1 file changed, 6 insertions(+), 2 deletions(-)
> >
> > diff --git a/src/libvirt-storage.c b/src/libvirt-storage.c
> > index a45c8b98c1..8738f6dd14 100644
> > --- a/src/libvirt-storage.c
> > +++ b/src/libvirt-storage.c
> > @@ -1590,7 +1590,9 @@ virStorageVolCreateXMLFrom(virStoragePoolPtr pool,
> > *
> > * Download the content of the volume as a stream. If @length
> > * is zero, then the remaining contents of the volume after
> > - * @offset will be downloaded.
> > + * @offset will be downloaded. Please note, that the data is
> > + * not interpreted and therefore data received by stream
> > + * client are in the very same format the volume is in.
>
> I don't think this wording clarifies it that much as it's not obvious
> what's meant by 'interpreted'.
>
> How about:
>
> Please note that the stream transports the volume itself as is, so the
> downloaded data may not correspond to guest OS visible state in cases
> when a complex storage format such as qcow2 or vmdk is used.
>
Fine by me.