On Mon, Nov 24, 2014 at 3:02 PM, Vasiliy Tolstov <v.tolstov(a)selfip.ru> wrote:
Hi. I'm try to shape disk via total_iops_sec in libvirt
libvirt 1.2.10
qemu 2.0.0
Firstly when i'm run vm with predefined
<total_iops_sec>5000</total_iops_sec> i have around 11000 iops (dd
if=/dev/sda bs=512K of=/dev/null)
After that i'm try to set via virsh --total_iops_sec 10 to want to
minimize io, but nothing changed.
After that i'm reboot vm with <total_iops_sec>10</total_iops_sec> and
get very slow io, but this expected. But libvirt says that i have is
around 600 iops.
My questions is - why i can't change total_iops_sec in run-time, and
why entered values does not equal values getting from libvirt ?
Thanks for any suggestions and any help.
--
Vasiliy Tolstov,
e-mail: v.tolstov(a)selfip.ru
jabber: vase(a)selfip.ru
Hello Vasiliy,
can you please check actual values via qemu-monitor-command domid '{
"execute": "query-block"}', just to be sure to pin the potential
problem to the emulator itself?