On Mon, Nov 24, 2014 at 3:02 PM, Vasiliy Tolstov <v.tolstov@selfip.ru> wrote:
Hi. I'm try to shape disk via total_iops_sec in libvirt libvirt 1.2.10 qemu 2.0.0
Firstly when i'm run vm with predefined <total_iops_sec>5000</total_iops_sec> i have around 11000 iops (dd if=/dev/sda bs=512K of=/dev/null) After that i'm try to set via virsh --total_iops_sec 10 to want to minimize io, but nothing changed. After that i'm reboot vm with <total_iops_sec>10</total_iops_sec> and get very slow io, but this expected. But libvirt says that i have is around 600 iops.
My questions is - why i can't change total_iops_sec in run-time, and why entered values does not equal values getting from libvirt ?
Thanks for any suggestions and any help.
-- Vasiliy Tolstov, e-mail: v.tolstov@selfip.ru jabber: vase@selfip.ru
Hello Vasiliy, can you please check actual values via qemu-monitor-command domid '{ "execute": "query-block"}', just to be sure to pin the potential problem to the emulator itself?