
On Tue, Jul 07, 2020 at 21:46:26 +0200, Michal Privoznik wrote:
This function will be used to detect zero buffers (which are going to be interpreted as hole in virStream later).
I shamelessly took inspiration from coreutils.
Coreutils is proudly GPLv3 ...
Signed-off-by: Michal Privoznik <mprivozn@redhat.com> --- src/libvirt_private.syms | 1 + src/util/virstring.c | 38 ++++++++++++++++++++++++++++++++ src/util/virstring.h | 2 ++ tests/virstringtest.c | 47 ++++++++++++++++++++++++++++++++++++++++ 4 files changed, 88 insertions(+)
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diff --git a/src/util/virstring.c b/src/util/virstring.c index e9e792f3bf..c26bc770d4 100644 --- a/src/util/virstring.c +++ b/src/util/virstring.c @@ -1404,3 +1404,41 @@ int virStringParseYesNo(const char *str, bool *result)
return 0; } + + +/** + * virStringIsNull:
IsNull might indicate that this does a check if the pointer is NULL. You are checking for NUL bytes.
+ * @buf: buffer to check + * @len: the length of the buffer + * + * For given buffer @buf and its size @len determine whether + * it contains only zero bytes (NUL) or not.
Given the semantics of C strings being terminated by the NUL byte I don't think this function qualifies as a string helper and thus should probably reside somewhere outside of virstring.h
+ * + * Returns: true if buffer is full of zero bytes, + * false otherwise. + */ +bool virStringIsNull(const char *buf, size_t len) +{ + const char *p = buf; + + if (!len) + return true; + + /* Check up to 16 first bytes. */ + for (;;) { + if (*p) + return false; + + p++; + len--; + + if (!len) + return true; + + if ((len & 0xf) == 0) + break; + }
Do we really need to do this optimization? We could arguably simplify this to: if (*buf != '\0') return false; return memcmp(buf, buf + 1, len - 1); You can then use the saved lines to explain that comparing a piece of memory with itself shifted by any position just ensures that there are repeating sequences of itself in the remainder and by shifting it by 1 it means that it checks that the strings are just the same byte. The check above then ensuers that the one byte is NUL.