On Thu, Dec 14, 2017 at 17:29:51 +0100, Andrea Bolognani wrote:
QEMU 2.7 and newer don't allow guests to start unless the
initial
vCPUs count is a multiple of the vCPU hotplug granularity, so
validate it and report an error if needed.
Resolves:
https://bugzilla.redhat.com/show_bug.cgi?id=1283700
Signed-off-by: Andrea Bolognani <abologna(a)redhat.com>
---
src/qemu/qemu_domain.c | 41 ++++++++++++++++++++++
tests/qemuxml2argvdata/cpu-hotplug-granularity.xml | 18 ++++++++++
tests/qemuxml2argvtest.c | 3 ++
3 files changed, 62 insertions(+)
create mode 100644 tests/qemuxml2argvdata/cpu-hotplug-granularity.xml
diff --git a/src/qemu/qemu_domain.c b/src/qemu/qemu_domain.c
index e93333669..632f330f7 100644
--- a/src/qemu/qemu_domain.c
+++ b/src/qemu/qemu_domain.c
@@ -3289,6 +3289,36 @@ qemuDomainDefValidateVideo(const virDomainDef *def)
}
+/**
+ * qemuDomainDefGetVcpuHotplugGranularity:
+ * @def: domain definition
+ * @granularity: return location for vCPU hotplug granularity
+ *
+ * With QEMU 2.7 and newer, vCPUs can only be hotplugged @granularity at
+ * a time; because of that, QEMU will not allow guests to start unless the
+ * initial number of vCPUs is a multiple of @granularity.
+ *
+ * Returns 0 on success, 1 if topology is not configured and -1 on error.
+ */
+static int
+qemuDomainDefGetVcpuHotplugGranularity(const virDomainDef *def,
+ unsigned int *granularity)
+{
+ if (!granularity)
+ return -1;
Why?
+
+ if (!def->cpu || def->cpu->sockets == 0)
+ return 1;
I think we assume '1' as threads here if it's not specified.
+
+ if (qemuDomainIsPSeries(def))
+ *granularity = def->cpu->threads;
+ else
+ *granularity = 1;
Why not just return the granularity rather than this weirdness?
+
+ return 0;
+}
+
+