On 01/29/2013 06:41 AM, John Ferlan wrote:
>>>> *(pm + (j / 8)) |= cpumap[j] << (8
* (j & 7));
FWIW: This path of code only occurs when
"(hv_versions.hypervisor <=
1)" - IOW really old code. I checked history and the code was added by
commit id '86247f2c'. Also since the target of the "|" operation is a
'uint64_t' (e.g. *(pm + (j / 8)), wouldn't the shift from 0->56 be OK
(e.g. (8 * (j & 7)))? That is it's not an 'int << (8*4)' it's
a
'uint64_t << (8*4)'.
Order of operations, broken down by type:
*(uint64_t* + (int / int)) |= unsigned char << (int * (int & int))
*(uint64_t* + int) |= unsigned char << int
*(uint64_t*) |= int << int
uint64_t = uint64_t | int
There really is a sign extension bug, because 'unsigned char << int'
uses 'int' math, but we then widen the int into uint64_t. If vcpu 31 is
turned on, we end up sign-extending and also enabling vcpus 32-63 at the
same time, which was not the goal.
When first approaching this I figured I didn't want to introduce a bug
into code that's been around a long time and that may not have any one
using it. I agree the line looks ugly and it did take me a bit to think
about it.
Just because no one has reported the bug or tested it lately doesn't
mean that the bug isn't there - it has been there a LONG time. :)
Mathematically what you propose with the memcpy() works; however, I come
from an architecture where a memcpy to an unaligned address causes a
fault
Such a memcpy() implementation would be flawed, and should be reported
as a bug to that vendor; thankfully, these days, most libc do not have
that flaw. The C standard guarantees that memcpy() is required to work
on unaligned copies (for a certain definition of work; you may still end
up splicing together unrelated portions of adjacent integers when
reading things back as integers, but byte-for-byte, the operation is
well-defined).
--
Eric Blake eblake redhat com +1-919-301-3266
Libvirt virtualization library
http://libvirt.org